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CorollaryStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
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CLIQUE is NP-complete

Statement

CLIQUE is NP-complete.

Facts & Assumptions

Given: An arbitrary CLIQUE instance (G,k).

[L1]

The previous theorem gives a polynomial-time many-one reduction from 3-SAT to CLIQUE, by 3SAT polynomial-time many-one reduces to CLIQUE.

[L2]

The language 3-SAT is NP-complete, by 3-SAT is NP-complete.

[L3]

A language is NP-complete exactly when it is NP-hard and belongs to NP, by NP-hard and NP-complete languages.

[F1]

A yes-instance of CLIQUE consists of a graph with k pairwise adjacent chosen vertices, by Clique, independent set, and vertex cover decision problems.

Proof

technique · direct
1.1

A certificate for (G,k)CLIQUE is a list of k vertices. One checks in polynomial time that the listed vertices are distinct and that every pair is adjacent, so CLIQUE lies in NP.

F1givenconstruct
1.2

Because [L2] says that 3-SAT is NP-complete, every language in NP reduces to 3-SAT. Composing any such reduction with the fixed reduction [L1] shows that every language in NP reduces to CLIQUE. Hence CLIQUE is NP-hard.

L1L2L3
2.1

Step 1.1 gives CLIQUE NP, and step 1.2 gives NP-hardness. Therefore CLIQUE is NP-complete by [L3].

L3step 1.1step 1.2

Depends on

Used by

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources