Alphabeta Math
CorollaryStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Closed forms have zero boundary integral

Statement

Assume ACω. For oriented Mn with boundary, n1, if ηΩcn1(M) is closed, then Mjη=0. When M is compact, no separate support assumption on the smooth closed form is needed.

Facts & Assumptions

[F1]

The general Stokes theorem: Assume ACω. Let M be an oriented smooth n-manifold with boundary, n1, and let ηΩcn1(M). With j:MM and the outward-normal-first orientation, Mdη=Mjη. An empty boundary contributes zero; in dimension one its integral is a finite signed sum of point values.

Proof

Given: The objects and hypotheses in the statement above.

1.1

Closedness says dη=0. General Stokes identifies the boundary integral with Mdη, which is the integral of the zero top form and hence zero. An empty boundary is included.

F1
2.1

For compact M every closed support is compact. Thus the same argument applies to every smooth closed (n1)-form. For n=1 it gives the signed sum of boundary values of a locally constant function; for the zero form all terms vanish.

step 1.1algebra

Depends on

Used by

Dependency tree · two levels

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Sources