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A C1 field on an open subset of R3 is closed exactly when its curl vanishes

Statement

Let U⊆R3 be open and let F:U→R3 be C1. Then a C1 field on an open subset of R3 is closed if and only if its curl vanishes identically: F is closed in the sense of Exact and closed C1 vector fields exactly when curl⁡F(p)=0 for every p∈U.

Facts & Assumptions

Given: The open set U⊆R3 and the C1 field F:U→R3 of the Statement, with the three coordinates named x,y,z as on this page.

[F1]

The curl of a C1 field F on an open U⊆R3 is curl⁡F=(∂yFz−∂zFy, ∂zFx−∂xFz, ∂xFy−∂yFx) (Divergence and curl of a C1 vector field).

[F2]

A C1 field F=(F0,…,Fn−1) on an open U⊆Rn, with coordinates and partial derivatives indexed from 0, is closed when ∂jFi=∂iFj for all i,j<n (Exact and closed C1 vector fields).

[F3]

For x∈Rn one writes xk:=x(k) for k<n (The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn).

Proof

technique · direct
1.1givenF2F3

By [F3] the coordinates of a point of R3 are indexed 0,1,2, and the names x,y,z used on this page are those three indices in that order; so the closedness condition of [F2] at n=3 is the system of equations ∂jFi=∂iFj ranging over all pairs i,j drawn from {x,y,z}.

1.2F2algebra

In that system the equations with i=j read ∂iFi=∂iFi and hold for every field, and the equation indexed (i,j) is the same equation as the one indexed (j,i). Hence the system is equivalent to its three equations indexed by the unordered pairs {y,z}, {z,x} and {x,y}.

2.1step 1.1step 1.2F1algebra

Written out, those three equations are ∂yFz=∂zFy, ∂zFx=∂xFz and ∂xFy=∂yFx. Their left-minus-right differences ∂yFz−∂zFy, ∂zFx−∂xFz and ∂xFy−∂yFx are, by [F1], exactly the first, second and third coordinates of curl⁡F.

3.1step 2.1F2F1

For the forward direction, suppose F is closed. By steps 1.1 and 1.2 the three equations of step 2.1 hold at every p∈U, so by [F1] each of the three coordinates of curl⁡F(p) is zero; hence curl⁡F vanishes identically on U.

3.2step 2.1F1F2

For the converse direction, suppose curl⁡F(p)=0 for every p∈U. By [F1] each of the three differences of step 2.1 is zero at every p, so the three equations of step 2.1 hold on U; by steps 1.1 and 1.2 these are equivalent to the full system of [F2], so F is closed.

4.1step 3.1step 3.2∎

Steps 3.1 and 3.2 are the two implications, so F is closed if and only if its curl vanishes identically.

Remarks

  • Why the count of equations matters. Closedness in Rn is a condition on all ordered pairs of indices, and the curl in R3 has three coordinates. Step 1.2 is what shows that these are the same amount of information: the diagonal equations are automatic and each off-diagonal equation is listed twice. In Rn with n≠3 the number of independent equations is n(n−1)/2, so there is no vector of that many coordinates in the same space to collect them into, and closedness is then stated only as the system itself.

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Sources