Alphabeta Math
CorollaryStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-31
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Turing machines admit an effective enumeration

Statement

The coded deterministic one-tape Turing machines of A fixed effective binary encoding of deterministic one-tape Turing machines can be effectively enumerated.

Facts & Assumptions

Given: The fixed coding of deterministic one-tape Turing machines.

[L1]

Every coded deterministic one-tape Turing machine M has a binary code M, by A fixed effective binary encoding of deterministic one-tape Turing machines.

[L2]

The chosen coding has a total decoder and is injective, by The chosen machine coding is injective and has a total decoder.

Proof

technique · direct
1.1

Enumerate all binary words in shortlex order and run the total decoder from [L2] on each word. Whenever the decoder reports malformed input, output nothing; whenever it returns a coded machine, output that machine.

L2givenconstruct
2.1

By [L1], every coded machine M has some binary code M, and shortlex enumeration eventually reaches that code. At that stage the decoder returns M, so every coded machine appears somewhere in the output stream.

L1step 1.1
3.1

By injectivity in [L2], two different binary words cannot decode to the same coded machine. Therefore the procedure from step 1.1 lists each coded deterministic one-tape Turing machine exactly once and gives an effective enumeration.

L2step 1.1step 2.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources