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CorollaryStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-28
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Over a splitting field, every G-endomorphism of an irreducible representation is scalar

Statement

Let G be a finite group, let k be a splitting field for G, and let V be an irreducible representation of G over k. Then every endomorphism in End⁡G(V) has the form λid⁡V with λ∈k.

Facts & Assumptions

Given: A finite group G, a splitting field k for G, and an irreducible representation V of G over k.

[L2]

By definition, a splitting field for G is a field over which every irreducible representation has endomorphism ring exactly k (A splitting field for a finite group: every irreducible representation has scalar endomorphism ring).

Proof

technique · direct
1.1L2given

By [L2], the endomorphism ring End⁡G(V) is exactly the scalar copy of k inside End⁡k(V).

2.1step 1.1L1∎

Therefore every G-endomorphism of V is λid⁡V for a unique λ∈k. Step 1.1 is compatible with the division-ring conclusion of [L1], which is why the scalar copy is a field.

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources