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Schur's lemma for irreducible representations: a nonzero intertwiner is an isomorphism, and is a division ring
Statement
Let and be irreducible representations of a group over a field . Then every nonzero intertwiner is an isomorphism. Consequently is a division ring.
Facts & Assumptions
Given: Irreducible representations and of over a field .
Irreducible representations are exactly simple -modules (Under the dictionary, subrepresentations are exactly submodules and irreducible representations are exactly simple modules).
-equivariant maps are exactly -module homomorphisms (For a commutative ring , -linear -actions are exactly the compatible left -module structures).
A nonzero homomorphism between simple modules is an isomorphism, and the endomorphism ring of a simple module is a division ring (Schur's lemma for simple modules).
Proof
By [L1], the irreducible representations and are simple -modules, and by [L2] a nonzero intertwiner is a nonzero -module homomorphism between them.
Applying [L3] to that module homomorphism shows that is an isomorphism. Applying [L3] with shows that is a division ring.
Depends on
Used by
Dependency tree · two levels
13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Peter Webb, A Course in Finite Group Representation Theory, Theorem 2.1.1 (standard reference, not scraped)
- Pavel Etingof et al., Introduction to Representation Theory, Proposition 1.16 (standard reference, not scraped)