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Every Grothendieck category has enough injectives, and every object admits an injective resolution
Statement
Assume the Axiom of Choice.
Every locally small Grothendieck category has enough injectives, and every object in it admits an injective resolution.
Facts & Assumptions
Given: A locally small Grothendieck category and an object of .
Grothendieck categories admit functorial injective embeddings (Grothendieck abelian categories have functorial injective embeddings).
A chosen injective embedding of the current cokernel extends a partial coaugmented resolution by one exact step (One-step extension of a partial injective resolution).
Enough injectives means that every object embeds in an injective object (A category with enough projectives and with enough injectives).
An injective resolution is an exact coaugmented complex of injectives (Injective resolutions in an abelian category).
Proof
By [L1], every object admits a monomorphism into an injective object. Therefore has enough injectives in the sense of [L3].
Starting from the functorial embedding from [L1], let be its cokernel and iterate the same functorial construction on successive cokernels. Applying [L2] at each stage yields an exact coaugmented complex of injectives.
By [L4], the complex from step 1.2 is an injective resolution of , including when . Because the embedding functor in [L1] is functorial, no additional arbitrary sequence of choices is introduced.
Depends on
Used by
Dependency tree · two levels
14 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- The Stacks Project, Section 19.11: Injectives in Grothendieck categories (standard reference, not scraped)
- Romyar Sharifi, Homological Algebra (standard reference, not scraped)