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False statementConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-09-01
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FALSE: objectwise projective-resolution choices uniquely determine a resolution functor

Statement

False. Once one projective resolution has been chosen for each object in a category with enough projectives, those objectwise choices uniquely determine comparison maps and hence a projective-resolution functor.

Facts & Assumptions

Given: The category of abelian groups and the standard projective resolution of Z/2Z.

[L1]

Enough projectives gives projective resolutions only after choosing successive projective epimorphisms for each fixed object (A chosen chain of projective epimorphisms gives a projective resolution).

[L2]

Finite-rank free modules are projective without any infinite choice (Free modules are projective, with the exact choice boundary).

Refutation

technique · direct
1.1L1

The proof of [L1] is objectwise: it chooses terms and differentials but supplies no unique lift of a morphism between resolved objects.

1.2L2algebra

The exact row 0→Z→2Z→Z/2Z→0 is a projective resolution by [L2]. On two copies of it, multiplication by 1 in both degrees and multiplication by 3 in both degrees are distinct chain maps lifting the identity of Z/2Z: both commute with multiplication by 2, and 3≡1(mod2). Thus the chosen objectwise resolution does not uniquely determine the map assigned to the identity morphism.

2.1step 1.1step 1.2∎

Therefore objectwise resolution choices do not uniquely determine comparison maps or a resolution functor; additional coherent choices or a separate functorial construction are required.

Depends on

Used by

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources