Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-01
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A chosen chain of projective epimorphisms gives a projective resolution

Statement

Let A be an object of an abelian category. Suppose one has chosen an epimorphism P0A with P0 projective and, for each n0, an epimorphism Pn+1Kn from a projective object onto the current kernel Kn of the previous displayed map. Then composing each chosen epimorphism with its kernel inclusion produces an augmented complex P2P1P0A0 that is a projective resolution of A.

Facts & Assumptions

Given: An object A of an abelian category, together with a chosen projective epimorphism onto A and a chosen projective epimorphism onto each successive kernel.

[L1]

A chosen projective epimorphism onto the current kernel extends a partial resolution by one exact step (One-step extension of a partial projective resolution).

[L2]

A projective resolution is an exact augmented complex of projective objects (Projective resolutions in an abelian category).

Proof

technique · direct
1.1

Start with the chosen epimorphism P0A. Applying [L1] to the chosen epimorphism P1K0 makes P1P0A0 exact, and repeating the same step with the chosen epimorphism onto each later kernel produces an augmented exact complex P2P1P0A0 whose terms are all projective.

L1givenconstruct
2.1

By [L2], the complex assembled in step 1.1 is a projective resolution of A, including the case A=0 when the chosen initial epimorphism may be 00.

L2step 1.1

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources