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For every forest , graphs excluding and have the Erdős-Hajnal property
Statement
For every forest , every finite graph with no induced and no induced has a clique or a stable set of size at least a positive power of its order. Equivalently, the hereditary class forbidding and has the Erdős-Hajnal property.
Facts & Assumptions
Given: A forest .
The class of graphs with no induced and no induced has the strong Erdős-Hajnal property (For every forest , graphs excluding and have a linear pure pair).
Every class defined by forbidden induced subgraphs is hereditary (Every class defined by forbidden induced subgraphs is hereditary).
Every hereditary class with the strong Erdős-Hajnal property has the Erdős-Hajnal property (The strong Erdős–Hajnal property implies the Erdős–Hajnal property).
Proof
Let be the class of finite graphs with no induced and no induced . By [L2], this is a hereditary class, and by [L1] it has the strong Erdős-Hajnal property.
Applying [L3] to gives the Erdős-Hajnal property for that class. This is the claimed graph-level statement.
Depends on
Used by
Dependency tree · two levels
15 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Maria Chudnovsky, Alex Scott, Paul Seymour, and Sophie Spirkl, Pure pairs. I. Trees and linear anticomplete pairs, statement 1.3 (standard reference, not scraped)