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TheoremStatement: Literature-sourcedProof: AI-generatedverified 2026-09-24 (gpt-6-sol)
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For every forest H, graphs excluding H and H‾ have a linear pure pair

Statement

For every forest H, there exists a real constant ϵH>0 such that every finite graph G with no induced H and no induced H‾ and with ∣V(G)∣≥2 contains disjoint sets A,B⊆V(G) satisfying

∣A∣≥ϵH∣V(G)∣,∣B∣≥ϵH∣V(G)∣,

and such that (A,B) is a pure pair. Equivalently, the hereditary class of graphs forbidding H and H‾ has the strong Erdős-Hajnal property.

Facts & Assumptions

Given: A forest H and a finite graph excluding both H and H‾.

[L1]

There is eH>0 such that every H-free graph on at least two vertices has an anticomplete pair with both sides at least eH times its order, or a vertex of degree at least eH times its order (Every forest-free graph has a linear anticomplete pair or a linear-degree vertex).

[L2]

For c∈(0,1/2), every nonempty H-free graph has a c-restricted set of size at least δ∣G∣ for some δ>0 depending on H,c (Rödl: for every H and every ϵ∈(0,12) there is δ>0 such that every nonempty H-free graph has an ϵ-restricted vertex set of size at least δ∣V(G)∣).

[L3]

The forbidden induced-subgraph class is hereditary (Every class defined by forbidden induced subgraphs is hereditary).

Proof

technique · apply Rödl's restricted-set theorem and the forest dichotomy
1.1

Choose 0<e≤eH with e<1/2 and apply [L2] with c=e/2, obtaining δ>0. Put ϵH=min⁡{eδ,δ}>0.

L1L2choose
2.1

Let G exclude H,H‾ and have n≥2 vertices. By [L2] it has X with ∣X∣≥δn which is either (e/2)-sparse or (e/2)-dense. If ∣X∣=1, then δn≤1; any two distinct vertices of G are a complete or anticomplete pair of singletons, both of size at least ϵHn.

step 1.1L2algebra
3.1

Suppose ∣X∣≥2 and X is (e/2)-sparse. The induced graph G[X] is H-free and has maximum degree at most (e/2)∣X∣<eH∣X∣. Therefore [L1] gives disjoint anticomplete A,B⊆X with ∣A∣,∣B∣≥eH∣X∣≥ϵHn.

step 1.1step 2.1L1
3.2

Suppose instead ∣X∣≥2 and X is (e/2)-dense. The complement G[X]‾ is H-free because G excludes H‾, and its maximum degree is at most (e/2)∣X∣. Apply [L1] there to obtain an anticomplete pair of size at least eH∣X∣ on each side; it is a complete pair of size at least ϵHn in G.

step 1.1step 2.1L1
4.1

All cases give a pure pair of the required linear size. By [L3] and the definition of strong Erdős–Hajnal property, the hereditary class excluding H,H‾ has that property.

step 2.1step 3.1step 3.2L3∎

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