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CorollaryStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-28
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Under the ultrafilter lemma, groups containing a rank-two free subgroup are nonamenable

Statement

Assume the ultrafilter lemma. If a group contains a free subgroup of rank 2, then it is nonamenable.

Facts & Assumptions

Given: A group G containing a subgroup HF2, and the ultrafilter lemma.

[L1]

The rank-two free group is nonamenable (The free group of rank two is nonamenable).

[L2]

Under the ultrafilter lemma, subgroups of amenable groups are amenable (Under the ultrafilter lemma, subgroups and quotients of amenable groups are amenable).

Proof

technique · direct
1.1

If G were amenable, then [L2] would make its subgroup H amenable.

L2givenassume-contra
2.1

But HF2, and [L1] says F2 is nonamenable. This contradiction proves that G is nonamenable.

L1step 1.1discharge-contradiction

Depends on

Used by

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources