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Under the ultrafilter lemma, amenability is a quasi-isometry invariant for finitely generated groups

Statement

Assume the ultrafilter lemma. Amenability is a quasi-isometry invariant of finitely generated groups.

Facts & Assumptions

Given: Two finitely generated quasi-isometric groups G and H, and the ultrafilter lemma.

[L1]

A property of finitely generated groups is a quasi-isometry invariant when it depends only on quasi-isometry type (Quasi-isometry invariants and geometric properties of finitely generated groups).

[L2]

Under the ultrafilter lemma, amenability is equivalent to the Folner condition (Under the ultrafilter lemma, the Folner condition is equivalent to amenability).

Proof

technique · direct
1.1

Choose word metrics on G and H, quasi-inverse quasi-isometries q:GH and r:HG, and constants λ1,c,DG,DH0 such that both maps satisfy the (λ,c) upper distance bound, dG(rq(x),x)DG, and dH(qr(y),y)DH. A fiber of q has uniformly bounded cardinality: if q(x)=q(x), the lower quasi-isometry inequality bounds dG(x,x), and a word-metric ball of fixed radius is finite. Let Mq bound those fibers, and define Mr similarly.

givenchoose
2.1

Assume G is amenable. Let EH be finite and let ε>0. Put L=max{e:eE}, taking L=0 when E=, set R=λ(L+DH)+c+DG, and let T be the finite radius-R ball in G. Set δ=ε/(2MqMr(T+1)). By [L2], choose a finite nonempty AG with tAA<δA for every tT.

L2step 1.1choose
3.1

Put B=NDH(q(A)). It is finite and nonempty, and Bq(A)A/Mq. If yNL(B)B, choose bB and aA with dH(y,b)L and dH(b,q(a))DH. Then dG(r(y),a)R. Moreover r(y)A, since otherwise dH(y,q(r(y)))DH would put y in B. Hence r(NL(B)B)NR(A)A, and the fiber bound for r gives NL(B)BMrNR(A)A.

step 1.1step 2.1algebra
4.1

Since NR(A)AtT(tAA), step 2.1 gives NR(A)A<TδA. For eE, one has eBBNL(B)B and eBB=2eBB. Combining this with step 3.1 and BA/Mq yields eBB/B<2MqMrTδ<ε. Thus B is an (E,ε)-Folner set in H.

step 2.1step 3.1algebra
5.1

Since E and ε were arbitrary, step 4.1 gives the Folner condition in H, so [L2] makes H amenable. Applying the same argument to the quasi-inverse transfers amenability from H to G. Therefore amenability depends only on quasi-isometry type, as asserted in [L1].

L1L2step 4.1

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