Alphabeta Math
CorollaryStatement: AI-adaptedProof: AI-adaptedprecheck passaudited 2026-08-13
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

If det⁡(A) is a unit, then A−1=det⁡(A)−1adj⁡(A)

Statement

If R is a commutative ring, n≥1, A∈Mn(R), and det⁡(A) is a unit, then

A−1=det⁡(A)−1adj⁡(A).

Facts & Assumptions

Given: R,n,A as in the statement.

[L1]

The adjugate identity is Aadj⁡(A)=adj⁡(A)A=det⁡(A)In (For every positive-sized square matrix over a commutative ring, Aadj⁡(A)=adj⁡(A)A=det⁡(A)I).

[L2]

A positive-sized square matrix whose determinant is a unit is invertible (A positive-sized square matrix over a commutative ring is invertible if and only if its determinant is a unit).

Proof

technique · direct
1.1

Put u=det⁡(A). Scaling [L1] by u−1 gives A(u−1adj⁡(A))=(u−1adj⁡(A))A=In.

L1algebra
2.1

By [L2], A−1 exists. Both it and u−1adj⁡(A) are two-sided inverses of A, so [L3] makes them equal.

step 1.1L2L3∎

Depends on

Used by

Dependency tree · two levels

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Sources