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CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-09-04
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Local Holder regularity implies Fourier convergence at a point

Statement

Assume the Axiom of Countable Choice.

Let f be a one-period integrable function and let xR. Suppose there are constants C>0, α>0, and δ(0,1/2) such that

f(x+t)f(x)Ctαandf(xt)f(x)Ctα

for every 0<t<δ. Then

SNf(x)f(x)as N.

Facts & Assumptions

Given: The Axiom of Countable Choice, a one-period integrable function f, a real x, constants C>0 and α>0, and a real δ with 0<δ<1/2 such that f(x+t)f(x)Ctαandf(xt)f(x)Ctα for every 0<t<δ.

[L1]

Assuming the Axiom of Countable Choice, if 0δf(x+t)+f(xt)2stdt<, then SNf(x)s (Dini pointwise convergence criterion for Fourier series).

Proof

technique · direct
1.1

For 0<t<δ, the triangle inequality and the hypotheses give f(x+t)+f(xt)2f(x)f(x+t)f(x)+f(xt)f(x)2Ctα.

L1givenalgebra
2.1

Therefore 0δf(x+t)+f(xt)2f(x)tdt2C0δtα1dt=2Cαδα<.

step 1.1algebra
3.1

Applying [L1] with s=f(x) and using step 2.1 gives SNf(x)f(x).

L1step 2.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources