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The logarithm of the modulus of a holomorphic function is plurisubharmonic
Statement
Let be a domain and let be holomorphic on , not identically zero on any connected component. Define
with the convention at the zeros of . Then is plurisubharmonic on .
Facts & Assumptions
Given: A holomorphic function on a domain , not identically zero on any connected component.
Plurisubharmonicity is tested on affine complex lines (Plurisubharmonic functions).
For a one-variable holomorphic function, the logarithm of the modulus is subharmonic with the value at its zeros (The logarithm of the modulus of a holomorphic function is subharmonic).
Proof
Fix an affine complex line in . The restriction of to that line is a one-variable holomorphic function, and by the componentwise hypothesis it is not identically zero on the connected component under consideration. Therefore [L2] makes the restriction of subharmonic or identically there.
The function is upper semicontinuous because it is a logarithm of a continuous modulus away from the zero set and has value on the zero set. Step 1.1 is exactly the line test from [L1], so is plurisubharmonic on .
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
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Sources
- Jiří Lebl, Tasty Bits of Several Complex Variables, §2.4 (standard reference, not scraped)
- Harold P. Boas, Lecture Notes on Several Complex Variables, §3.2.4 (standard reference, not scraped)