Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-28
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The logarithm of the modulus of a holomorphic function is plurisubharmonic

Statement

Let Ω⊆Cm be a domain and let f be holomorphic on Ω, not identically zero on any connected component. Define

u(z)=log⁡∣f(z)∣,

with the convention u(z)=−∞ at the zeros of f. Then u is plurisubharmonic on Ω.

Facts & Assumptions

Given: A holomorphic function f on a domain Ω⊆Cm, not identically zero on any connected component.

[L1]

Plurisubharmonicity is tested on affine complex lines (Plurisubharmonic functions).

[L2]

For a one-variable holomorphic function, the logarithm of the modulus is subharmonic with the value −∞ at its zeros (The logarithm of the modulus of a holomorphic function is subharmonic).

Proof

technique · direct
1.1L2given

Fix an affine complex line in Ω. The restriction of f to that line is a one-variable holomorphic function, and by the componentwise hypothesis it is not identically zero on the connected component under consideration. Therefore [L2] makes the restriction of u=log⁡∣f∣ subharmonic or identically −∞ there.

2.1L1step 1.1∎

The function u is upper semicontinuous because it is a logarithm of a continuous modulus away from the zero set and has value −∞ on the zero set. Step 1.1 is exactly the line test from [L1], so u is plurisubharmonic on Ω.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources