Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-28
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Maximum principle for plurisubharmonic functions

Statement

Let u be plurisubharmonic on a domain ΩCm. If u attains its finite global maximum at a point of Ω, then u is constant on Ω.

Facts & Assumptions

Given: A plurisubharmonic function u on a domain ΩCm and a point aΩ with u(a)=supΩu<+.

[L1]

Plurisubharmonicity is tested by subharmonicity on every affine complex line (Plurisubharmonic functions).

[L2]

A subharmonic function of one complex variable that attains a finite interior maximum is constant on its connected component (A plane subharmonic function with an interior maximum is constant on its component).

Proof

technique · direct
1.1

Choose a small Euclidean ball B(a,r)Ω. Fix zB(a,r), and restrict u to the affine complex line through a and z. By [L1], that restriction is subharmonic on the connected line-domain component containing the segment from a to z, and the global bound makes its value at a a finite maximum. Hence [L2] makes it constant on that component, so u(z)=u(a). Thus u is constant on B(a,r).

L1L2given
2.1

Put S:={zΩ:u(z)=u(a)}. It is nonempty. Every point of S is another point where the finite global maximum is attained, so the argument of step 1.1 makes S open. Since uu(a) everywhere and upper semicontinuity makes {uu(a)} closed, S={uu(a)} is closed. Connectedness of Ω gives S=Ω, so u is constant.

step 1.1given

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