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CorollaryStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-sol)audited 2026-09-27
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Agreement on a schematically dense open

Statement

Assume the Axiom of Choice. Let Y→S be a separated morphism, let X be an S-scheme and let U⊆X be an open subscheme such that OX→j∗OU is injective, where j:U→X is the inclusion. Then any two S-morphisms a,b:X→Y with a∣U=b∣U are equal. In particular this holds when X is reduced and U is a topologically dense open subscheme.

Facts & Assumptions

Given: S-morphisms a,b:X→Y with Y→S separated, an open subscheme j:U→X with OX→j∗OU injective, and the Axiom of Choice (The Axiom of Choice).

[F1]

Under the hypothesis that Y→S is separated, the equalizer of a and b exists as a closed subscheme e:E↪X and represents agreement: for every scheme T, the morphisms T→E correspond bijectively to the t:T→X with at=bt. (Equalizers into separated schemes are closed)

[F2]

For a scheme X the nilradical ideal sheaf NX has nilpotent germs, NX(U) consists of the locally nilpotent sections on U, on Spec⁡A the reduction is Spec⁡(A/(0)), and X is reduced exactly when NX=0. (The reduction of a scheme)

[F3]

An affine scheme is reduced when its coordinate ring is reduced, that is, has no nonzero nilpotent element. (Reduced affine schemes)

[F4]

A closed immersion e:E→X has OX→e∗OE surjective and is a homeomorphism onto a closed subset of X. (Closed immersions of schemes)

[F5]

Assume AC: in a nonzero commutative ring every proper ideal is contained in a maximal ideal, and a maximal ideal is prime, so every nonzero commutative ring has a prime ideal. (In a nonzero commutative ring, every proper ideal is contained in a maximal ideal, Every maximal ideal of a commutative ring is prime)

Proof

technique · direct
1.1

Injectivity of OX→j∗OU means that for every open W⊆X a section s∈OX(W) with s∣W∩U=0 is zero; it suffices to test this for affine W, since these form a basis of the topology.

given
1.2

Because a∣U=b∣U, the inclusion j:U→X satisfies aj=bj; so by the universal property of [F1] there is a morphism U→E whose composite with the closed immersion e:E→X is j.

F1given
1.3

By [F4] the map e♯:OX→e∗OE is surjective.

F4
2.1

The composite OX→e♯e∗OE→j∗OU of structure-sheaf maps corresponding to e and to the factorization j=e∘(U→E) is the restriction map OX→j∗OU of the inclusion j.

F4step 1.2
3.1

The composite of step 2.1 equals the injective map OX→j∗OU, hence is injective; since e♯ is surjective by step 1.3 and its composite with the next map is injective, e♯ is injective as well. Therefore e♯ is an isomorphism of sheaves.

step 2.1step 1.3
4.1

Step 3.1 reduces the corollary to its stated hypothesis; it remains to verify that hypothesis in the reduced case. Let X be reduced and U topologically dense, let W=Spec⁡A be a nonempty affine open and let s∈A satisfy s∣W∩U=0. Suppose s≠0. By [F2] and [F3] the ring A is reduced, so s is not nilpotent and the localization As is a nonzero ring; by [F5] the nonzero ring As has a maximal ideal, hence a prime ideal, whose contraction is a prime p⊆A with s∉p, so D(s)⊆W is a nonempty open subset. If x∈D(s)∩(W∩U), then sx=0 in OW,x=Apx because s vanishes on W∩U, while s∉px together with primality of px shows that no t∉px has ts=0, so sx≠0; hence D(s)∩(W∩U)=∅, contradicting density of U in X, since the nonempty open D(s)⊆W must meet U; the exact use of the Axiom of Choice is [F5] producing p. Hence s=0, and by step 1.1 the map OX→j∗OU is injective.

F2F3F5step 1.1step 3.1
5.1

Combining step 3.1 with step 4.1: if X is reduced and U is a topologically dense open subscheme, then OX→j∗OU is injective, and then a∣U=b∣U forces a=b by step 3.1.

step 3.1step 4.1∎

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