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CorollaryStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-12
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Normal p core lies in every block defect group

Statement

For a finite group G, its largest normal p-subgroup Op(G) lies in every block defect group over a field of characteristic p.

Facts & Assumptions

Given: A finite group G and a defect group D.

[F1]

A defect group is an intersection of two Sylow p-subgroups. (Block defect is an intersection of two sylow subgroups)

Proof

technique · direct
1.1given

For finite K, the product of two normal p-subgroups N1,N2 is normal and is a subgroup; its order is ∣N1∣∣N2∣/∣N1∩N2∣, a power of p. The order formula follows because each element of the product has exactly ∣N1∩N2∣ representations as n1n2. There are finitely many subgroups of K, so their finite product defines the largest normal p-subgroup Op(K), including the trivial subgroup. If T is Sylow and N⊴K is a p-subgroup, the same order formula makes NT a p-subgroup containing T; maximality of T forces NT=T. Thus N≤T.

2.1F1F2step 1.1∎

Choose a Sylow P containing D by [F2]. By [F1], D=P∩hPh−1 for some h. Apply step 1.1 to both Sylow subgroups to obtain Op(G)≤P∩hPh−1=D.

Sources

Webb, A Course in Finite Group Representation Theory, §§11.3, 11.6 and 12.3–12.5, especially pp.240–245. Local argument and conventions as displayed above.

Depends on

Used by

Dependency tree · two levels

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Sources