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CorollaryStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-12
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Block defect groups are p radical

Statement

Every block defect group satisfies D=Op(NG(D)).

Facts & Assumptions

Given: A defect group D of a block of a finite group G over a field of characteristic p.

[F1]

For every Sylow P≥D there is h∈CG(D) with D=P∩hPh−1. (Block defect is an intersection of two sylow subgroups)

Proof

technique · direct
1.1F1F2

Put N=NG(D). Choose a Sylow subgroup T of N containing D, and a Sylow subgroup P of G containing T, by [F2]. Then P∩N is a p-subgroup of N containing its Sylow subgroup T, hence equals T. Take h∈CG(D)⊆N from [F1]. Intersecting D=P∩hPh−1 with N gives D=(P∩N)∩h(P∩N)h−1=T∩hTh−1.

2.1step 1.1∎

The product of normal p-subgroups of a finite group is a normal p-subgroup: for two factors its order is the product of their orders divided by the intersection order, by counting representations of a product element. A finite product over all such subgroups therefore defines Op(N). If V is Sylow in N, normality makes Op(N)V a p-subgroup containing V, hence equal to V. Thus Op(N) lies in both T and hTh−1, so in D by step 1.1. Conversely D⊴N by the definition of its normalizer and D is a p-group, so D≤Op(N). Both inclusions prove equality.

Sources

Webb, A Course in Finite Group Representation Theory, §§11.3, 11.6 and 12.3–12.5, especially pp.240–245. Local argument and conventions as displayed above.

Depends on

Used by

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Sources