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CorollaryStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
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Every finite graph has a bounded partition into self-regular vertex sets

Statement

For every 0<ϵ<1 there is K=K(ϵ) such that the vertex set of every finite graph can be partitioned into at most K sets, each of which is ϵ-self-regular.

Facts & Assumptions

Given: 0<ϵ<1 and a finite graph G.

[L1]

At every smaller regularity parameter, every finite graph with at least one vertex has a nonempty self-regular set containing a fixed positive fraction of its vertices (Every finite graph has a linearly large ϵ-self-regular vertex subset).

[L2]

Given ϵ<ϵ, sufficiently small vertex and edge changes preserve regularity with parameter ϵ (Regularity survives sufficiently small changes of vertices and cross-edges).

Proof

technique · direct
1.1

Apply [L2] with old parameter ϵ/2 and new parameter ϵ, and let τ>0 be a permitted relative vertex-change fraction. Let δ>0 be supplied by [L1] at parameter ϵ/2.

givenL1L2choose
2.1

Repeatedly apply [L1] to the graph induced by the vertices not yet chosen, stopping if that remainder is empty and otherwise removing an (ϵ/2)-self-regular set of at least a δ fraction of it. Choose a fixed r with (1δ)rτ/(1+τ). After at most r rounds, the unassigned remainder has size at most τ times the size of the union of the extracted sets.

step 1.1L1inductionalgebra
3.1

Distribute every remaining vertex among the at most r extracted sets proportionally to their sizes. For all sufficiently large graph orders, rounding can be absorbed by replacing τ in step 1.1 with a smaller constant, so no set grows by more than the vertex-change fraction allowed by [L2]. No old incidence among vertices of an extracted set is changed.

step 2.1L2choosealgebra
4.1

By [L2], every enlarged set is ϵ-self-regular. Empty and bounded exceptional graphs may instead be partitioned into singletons, increasing the uniform bound only by a constant; hence some K(ϵ) works for all finite graphs.

step 3.1L2induction

Depends on

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Direct dependencies and their dependencies through the next three levels: 9 results over 8 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

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