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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-16
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Every finite graph has a linearly large ϵ-self-regular vertex subset

Statement

For every 0<ϵ<1 there is δ=δ(ϵ)>0 such that every finite graph G with at least one vertex has a nonempty set W⊆V(G) with ∣W∣≥δ∣V(G)∣ and (W,W) is ϵ-regular. The hypothesis that G is nonempty cannot be dropped: ϵ-self-regularity is defined only for nonempty vertex sets.

Facts & Assumptions

Given: 0<ϵ<1 and a finite graph G with at least one vertex.

[L1]

For arbitrarily small parameters and prescribed minimum part counts, every sufficiently large graph has a bounded equitable regular partition (Szemerédi regularity lemma with an equitable partition and an explicit tower-type upper bound for graphs of order at least m0).

[L2]

A set W is ϵ-self-regular when every two subsets of W of size at least ϵ∣W∣ have density within ϵ of d(W,W) (ϵ-regular pairs and self-regular vertex sets).

Proof

technique · direct
1.1givenchooseinduction

Choose an integer s≫ϵ−3 and divide [0,1] into q=⌈8/ϵ⌉ intervals of length at most ϵ/8. Repeated pigeonhole selection gives an integer R=R(q,s) such that every q-colouring of the pairs of an R-set has a monochromatic s-set: select successively a vertex and a colour occurring on at least a 1/q fraction of its remaining incident pairs, and take the initial set large enough for s selections.

2.1step 1.1L1choose

Choose ρ>0 much smaller than R−2ϵ3, apply [L1] at parameter ρ and minimum part count much larger than R/ϵ, and let M be the resulting upper bound on the number of parts.

3.1step 2.1L1algebra

In the graph on the partition indices whose edges are the regular cross-pairs, fewer than 2ρk2 pairs are missing by equitability. If every R-set contained a missing pair, double-counting pairs inside R-sets would force at least (k2)/(R2) missing pairs, contrary to the choice of ρ. Hence there is an R-set of indices all of whose cross-pairs are ρ-regular.

4.1step 1.1step 3.1choosealgebra

Colour those regular pairs by the interval containing their density. Step 1.1 supplies s parts V1,…,Vs whose cross-densities all lie in one interval; let W=V1∪⋯∪Vs. Since the partition is equitable and has at most M parts, ∣W∣≥sn/(2M).

5.1step 2.1step 4.1algebra

Let A,B⊆W have size at least ϵ∣W∣, and write Ai=A∩Vi, Bj=B∩Vj. Pairs with i=j, or with ∣Ai∣<ρ∣Vi∣ or ∣Bj∣<ρ∣Vj∣, contribute at most 3/(ϵ2s)+4ρ/ϵ to the normalized density comparison.

6.1step 4.1step 5.1L2algebra

On every remaining pair, regularity gives ∣d(Ai,Bj)−d(Vi,Vj)∣≤ρ, while the density colour in step 4.1 makes any two cross-densities differ by at most ϵ/8. Decomposing both d(A,B) and d(W,W) over the s2 pairs and using step 5.1 therefore gives ∣d(A,B)−d(W,W)∣≤ϵ by the choices of s and ρ.

7.1step 2.1step 4.1step 6.1L1L2choose∎

For graphs large enough for [L1], steps 4.1 and 6.1 give an ϵ-self-regular W of size at least sn/(2M). For the finitely many smaller orders n≥1, a singleton is 0-self-regular and hence ϵ-self-regular. Shrinking δ to the minimum of s/(2M) and the reciprocals of those orders proves the Statement for every finite graph with at least one vertex.

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