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Every finite graph has a linearly large -self-regular vertex subset
Statement
For every there is such that every finite graph with at least one vertex has a nonempty set with and is -regular. The hypothesis that is nonempty cannot be dropped: -self-regularity is defined only for nonempty vertex sets.
Facts & Assumptions
Given: and a finite graph with at least one vertex.
For arbitrarily small parameters and prescribed minimum part counts, every sufficiently large graph has a bounded equitable regular partition (Szemerédi regularity lemma with an equitable partition and an explicit tower-type upper bound for graphs of order at least ).
A set is -self-regular when every two subsets of of size at least have density within of (-regular pairs and self-regular vertex sets).
Proof
Choose an integer and divide into intervals of length at most . Repeated pigeonhole selection gives an integer such that every -colouring of the pairs of an -set has a monochromatic -set: select successively a vertex and a colour occurring on at least a fraction of its remaining incident pairs, and take the initial set large enough for selections.
Choose much smaller than , apply [L1] at parameter and minimum part count much larger than , and let be the resulting upper bound on the number of parts.
In the graph on the partition indices whose edges are the regular cross-pairs, fewer than pairs are missing by equitability. If every -set contained a missing pair, double-counting pairs inside -sets would force at least missing pairs, contrary to the choice of . Hence there is an -set of indices all of whose cross-pairs are -regular.
Colour those regular pairs by the interval containing their density. Step 1.1 supplies parts whose cross-densities all lie in one interval; let . Since the partition is equitable and has at most parts, .
Let have size at least , and write , . Pairs with , or with or , contribute at most to the normalized density comparison.
On every remaining pair, regularity gives , while the density colour in step 4.1 makes any two cross-densities differ by at most . Decomposing both and over the pairs and using step 5.1 therefore gives by the choices of and .
For graphs large enough for [L1], steps 4.1 and 6.1 give an -self-regular of size at least . For the finitely many smaller orders , a singleton is -self-regular and hence -self-regular. Shrinking to the minimum of and the reciprocals of those orders proves the Statement for every finite graph with at least one vertex.
Depends on
Used by
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 11 results over 9 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- Y. Zhao, Graph Theory and Additive Combinatorics, Theorem 2.1.26 and Exercise 2.1.27 (standard reference, not scraped)