Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A planar graph contains no subdivision of K5K_5 or K3,3K_{3,3}

Facts & Assumptions

Given: A planar graph GG.

[L1]

K5K_5 and K3,3K_{3,3} are nonplanar (K5K_5 and K3,3K_{3,3} are nonplanar).

[F1]

Proof

technique · contradiction
1.1

In a plane drawing of a subdivision, suppressing a degree-two subdivision vertex replaces its two incident polygonal edge arcs by their concatenation and preserves a plane drawing. Repeating this suppression shows that planarity of a subdivision implies planarity of the original graph.

F1
2.1

Suppose GG contained a subdivision of K5K_5 or K3,3K_{3,3}. A subgraph of a planar graph inherits a plane drawing, and step 1.1 would turn that drawing into a plane drawing of the corresponding original graph, contradicting [L1].

assume-contrastep 1.1L1F1discharge-contradiction

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 31 results over 8 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources