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PropositionStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
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For a two-connected planar graph of order at least three, maximal planarity is equivalent to having 3n63n-6 edges

Statement

Let GG be a simple planar graph with n3n\ge3 vertices. If GG has exactly 3n63n-6 edges, then GG is maximally planar in the sense of Maximal plane graphs, plane triangulations, and maximally planar abstract graphs. Conversely, if GG is two-connected and maximally planar, then GG has exactly 3n63n-6 edges. The two conditions are therefore equivalent for two-connected GG. Two-connectivity is used only through A two-connected plane graph of order at least three is maximal exactly when every face is triangular, which needs a facial boundary to be a cycle; the converse without that hypothesis is not established here.

Facts & Assumptions

Given: Such a planar graph GG.

[L1]

Every simple planar graph with n3n\ge3 vertices and mm edges satisfies m3n6m\le3n-6. Every plane triangulation with at least three vertices has equality (Every simple planar graph with n3n\ge3 vertices has at most 3n63n-6 edges, with equality for every plane triangulation).

[L2]

A two-connected plane graph of order at least three is maximal exactly when every face is triangular (A two-connected plane graph of order at least three is maximal exactly when every face is triangular).

Proof

technique · direct
1.1

Let GG be two-connected and maximally planar. Every plane embedding of GG is maximal plane: otherwise an edge added in that embedding would give a larger planar abstract graph. That embedding is a two-connected plane graph, because two-connectivity is a property of the abstract graph, so [L2] makes it a triangulation and [L1] gives E(G)=3n6|E(G)|=3n-6.

L1L2
2.1

Conversely, if E(G)=3n6|E(G)|=3n-6 and a missing edge could be added planarly, the resulting simple planar graph on the same nn vertices would have 3n53n-5 edges, contradicting [L1]. Thus GG is maximally planar.

step 1.1L1
3.1

Step 2.1 holds for every n3n\ge3, and step 1.1 supplies the converse whenever GG is two-connected, so the two conditions are equivalent there.

step 1.1step 2.1

Depends on

Used by

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