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CorollaryStatement: AI-adaptedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-07-31
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A real power series converges absolutely inside its radius and diverges outside it, while either behaviour may occur at an endpoint

Statement

Let an(xc)n\sum a_n(x-c)^n have radius RR. It converges absolutely at every xx with xc<R|x-c|<R and diverges at every xx with xc>R|x-c|>R. When 0<R<+0<R<+\infty, no common conclusion holds at either endpoint c±Rc\pm R: power series of radius RR can converge there, even absolutely, or diverge there.

Facts & Assumptions

Given: A real power series an(xc)n\sum a_n(x-c)^n with radius RR (A real power series about a centre, its interval of convergence, and its radius in [0,+][0,+\infty]).

[L1]

Cauchy-Hadamard identifies RR from the limit superior of the coefficient roots and the root test gives absolute convergence below the reciprocal threshold and divergence above it (Cauchy–Hadamard: the reciprocal radius is lim supkak+11/(k+1)\limsup_{k\to\infty}|a_{k+1}|^{1/(k+1)}, with the zero and infinite cases included).

[L2]

At root-test boundary value 11, the coefficient families 1/(n+1)1/(n+1) and 1/(n+1)21/(n+1)^2 both have root limit superior 11, while the first series diverges and the second converges; changing the coefficient signs does not change their absolute values (Root test: lim supak1/k<1\limsup |a_k|^{1/k} < 1 gives absolute convergence and hence convergence, >1> 1 gives divergence, and =1= 1 decides nothing, claim 3).

Proof

technique · direct
1.1

The assertions for xc<R|x-c|<R and xc>R|x-c|>R are exactly the two strict alternatives supplied by [L1], including the cases R=0R=0 and R=+R=+\infty.

L1
1.2

For endpoint behaviour at radius 11, the series with coefficients 1/(n+1)21/(n+1)^2 converges absolutely at both x=1x=1 and x=1x=-1. The series with coefficients 1/(n+1)1/(n+1) diverges at x=1x=1, while the series with coefficients (1)n/(n+1)(-1)^n/(n+1) diverges at x=1x=-1. All three have radius 11 by [L2].

L2
2.1

Replacing xx by (xc)/R(x-c)/R and multiplying coefficients by the corresponding powers of R1R^{-1} transports the two radius-one examples to any finite R>0R>0 and centre cc. Thus either behaviour may occur at an endpoint, while no assertion has been made when the endpoints are not real.

step 1.2algebra

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