Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedprecheck passaudited 2026-07-31
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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A convergent real power series with nonzero constant term has a convergent reciprocal power series on a smaller neighbourhood

Statement

Let f(x)=∑n≥0an(x−c)n have positive radius and a0≠0. Then on some neighbourhood of c, 1/f is represented by a convergent real power series about c.

Facts & Assumptions

Proof

technique · constructive
1.1

Write f=a0+h, where h(c)=0. By absolute convergence, choose r>0 inside the radius so small that Br:=∑n≥1∣an∣rn<∣a0∣.

constructL2choose
2.1

By [L1], 1/f(x)=a0−1∑m≥0(−h(x)/a0)m for ∣x−c∣≤r. Expand each power by [L3].

step 1.1L1L3
3.1

The total absolute sum of the expanded terms is bounded by ∣a0∣−1∑m(Br/∣a0∣)m<∞. By [L4], regrouping by powers of x−c gives a convergent reciprocal power series on the neighbourhood.

step 1.1step 2.1L1L4discharge-construct∎

Depends on

Used by

Dependency tree · two levels

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Sources