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CorollaryStatement: Literature-sourcedProof: Literature-sourcedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
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The spectrum of a principal localisation is the distinguished open D(f)

Statement

Let R be a commutative ring and let f∈R. The localisation map R→Rf induces a homeomorphism from Spec⁡(Rf) onto the distinguished open subset D(f)={p∈Spec⁡(R):f∉p}.

Facts & Assumptions

Given: A commutative ring R and an element f∈R.

[L1]

For a localization at a multiplicative set S, the spectrum identifies homeomorphically with the primes of R disjoint from S (The spectrum of a localisation is the subspace of primes disjoint from the denominator set).

[L2]

D(f) is the set of prime ideals of R that do not contain f (Principal distinguished subsets of the prime spectrum).

Proof

technique · direct
1.1L1

Apply [L1] with S={1,f,f2,…}. Its image consists of the prime ideals p such that p∩S=∅.

1.2L2givenalgebra

For a prime ideal p, the condition p∩{1,f,f2,…}=∅ is equivalent to f∉p, because f∈p implies fn∈p for every n≥1, while fn∈p implies f∈p by primality. By [L2], this image is exactly D(f).

2.1step 1.1step 1.2∎

Therefore Spec⁡(Rf) is homeomorphic to the distinguished open subset D(f).

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources