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CorollaryStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Singular cohomology is homotopy invariant

Statement

Homotopic continuous maps f,g:XY induce the same pullback on Hsingk(;R) in every integer degree. Consequently a homotopy equivalence induces an isomorphism of real singular cohomology.

Facts & Assumptions

Given: A supplied continuous homotopy H:X×[0,1]Y from f to g.

[F1]

Postcomposition is a real-linear chain map and respects composition and identities (Singular chains are covariantly functorial).

[F2]

Real cohomology is the quotient of cocycles by coboundaries (Real singular cohomology).

[F3]

The supplied signed prism has g#f#=P+P, with the zero-degree formula g#,0f#,0=P0 (The singular chain homotopy formula).

Proof

1.1

Set fφ=φf#. The chain equation [F1] gives δf=fδ, hence f preserves cocycles and coboundaries and induces a real-linear map on the quotient [F2]. The generator identity and composition laws in [F1] become id=id and (gf)=fg.

F1F2algebra
1.2

Put Kkφ=φPk1 for k1 and Kk=0 for k0. For a degree-k cochain and cCk(X;R), [F3] gives (gf)φ(c)=φ(Pkc+Pk1c)=(Kk+1δφ+δKkφ)(c). In degree zero the second summand is zero, exactly as in [F3]; negative degrees are zero.

F2F3algebra
2.1

If φ is a cocycle, step 1.2 says gφfφ=δKkφ, so their classes coincide. If f:XY has a supplied homotopy inverse h:YX, apply this equality to hfidX and fhidY; step 1.1 yields fh=id and hf=id. Thus f is an isomorphism.

F2step 1.1step 1.2algebra
3.1

Empty spaces and negative groups have only zero maps, and on a point the identity acts identically on H0=R. Constant homotopies and degenerate simplices need no normalization: [F3] applies to their full signed prisms as well. Only the given homotopy and its explicit finite prism are used, so no AC is needed.

F2F3step 1.2step 2.1

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Sources