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CorollaryStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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One local place is determined by the others for ternary forms

Statement

Let q=aX2+bY2+cZ2 be a nondegenerate ternary diagonal form over Q. If q is isotropic over Qv for every place v except possibly one place w, then q is isotropic over Qw as well.

Facts & Assumptions

Given: A nondegenerate ternary form q=aX2+bY2+cZ2 over Q and a place w.

[L1]

The local isotropy criterion is q isotropic over Qv  ⟺  (−ac,−bc)v=1 (Ternary isotropy via the Hilbert symbol).

[L2]

The global reciprocity law is ∏v(x,y)v=1 (Hilbert reciprocity over the rationals).

Proof

technique · direct
1.1L1L2givenalgebra

For each place v≠w, the assumed isotropy and [L1] give (−ac,−bc)v=1. Multiplying these identities over all v≠w and using [L2] with x=−ac, y=−bc forces (−ac,−bc)w=1 as well.

2.1L1step 1.1algebra∎

Applying [L1] again at the place w shows that q is isotropic over Qw.

Depends on

Used by

Dependency tree · two levels

10 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources