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CorollaryStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6.1-sol)
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Time reversal of the homogeneous wave equation

Statement

Let c>0, let I⊆R be an open interval and let u∈C2(Rn×I) satisfy □cu=0 on Rn×I. For τ∈I define v(x,t):=u(x,2τ−t) for t∈2τ−I. Then □cv=0 on Rn×(2τ−I), and v(⋅,τ)=u(⋅,τ),∂tv(⋅,τ)=−∂tu(⋅,τ). Thus the homogeneous wave flow is reversible: the same equation propagates the time-reversed state, and the velocity is negated.

Facts & Assumptions

Given: an open interval I, a parameter τ∈I, a C2 function u on Rn×I with □cu=0, and v(x,t)=u(x,2τ−t) on Rn×(2τ−I).

[F1]

If g is totally differentiable at a and f at g(a), then f∘g is totally differentiable at a with D(f∘g)(a)=Df(g(a))∘Dg(a) (The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a)). The required total differentiability follows from continuous coordinate partial derivatives (If all partial derivatives exist on a neighbourhood and are continuous at a point, then the map is totally differentiable there with Jacobian derivative).

Proof

1.1F1F2algebra

Apply [F1] to the composition (x,t)↦(x,2τ−t)↦u(x,2τ−t): the inner map is affine with differential (h,s)↦(h,−s), so ∂tv(x,t)=−∂tu(x,2τ−t); applying the same rule once more, ∂t2v(x,t)=(−1)2∂t2u(x,2τ−t)=∂t2u(x,2τ−t). In the spatial directions the inner map is the identity, so ∂xjv(x,t)=∂xju(x,2τ−t) for each j and hence Δv(x,t)=Δu(x,2τ−t).

2.1F2algebra∎

Therefore for every (x,t) with t∈2τ−I, □cv(x,t)=∂t2u(x,2τ−t)−c2Δu(x,2τ−t)=□cu(x,2τ−t)=0, while at t=τ the substitutions 2τ−τ=τ give v(x,τ)=u(x,τ) and ∂tv(x,τ)=−∂tu(x,τ). This is the reversibility of the homogeneous wave flow.

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