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The Brownian transition semigroup

Definition

Assume the Axiom of Choice. Let B be a standard Brownian motion Brownian motion. For t>0 define the Brownian transition kernel pt(x,y):=(2πt)1/2exp ⁣((yx)22t),x,yR, and for every bounded Borel function f:RR define Ptf(x):=Rf(y)pt(x,y)dy(t>0),P0f:=f. The family (Pt)t0 is the Brownian transition semigroup, and each Pt is a transition operator.

Two equivalent descriptions are part of the definition and are used below.

  1. Expectation form. For a standard Brownian motion B as in Brownian motion and t0, Ptf(x)=E[f(x+Bt)]. Under AC, N(0,t) is the law of tZ for a standard normal Z, whose density φ(z)=ez2/2/2π is fixed in Standard normal and normal laws; the density of N(x,t) is the translate ypt(x,y), and the agreement of the two displayed expressions is proved as the first assertion of the semigroup lemma later on this page.
  2. Basic regularity. For t>0 the map (x,y)pt(x,y) is continuous, hence Borel; consequently Ptf is Borel for bounded Borel f, Pt is linear, and Ptff, with equality for f1 once the kernel is known to be a probability density. At t=0 the convention is P0f=f, so P0 is the identity.

The cases t=0 and s=0 of every later identity are the identity operator and are recorded separately rather than derived from the t>0 formula. No choice beyond the declared AC is made by the kernel: the integral is a Lebesgue integral of a fixed continuous density.

Source notes

Lawler, Section 2.6, and Durrett, Section 7.3, define the Brownian transition density and the operator Ptf. The expectation form is the definition of Pt in Lawler's Markov-viewpoint treatment; here it is stated as an equivalent description and proved in the following lemma, so that no step of the later arguments has to treat it as an extra hypothesis.

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