Alphabeta Math
DefinitionDefinition: Literature-sourcedProof: Not applicablePipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-08-29
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The condition number kappa_p(A) = ||A||_p ||A^{-1}||_p of a nonsingular linear system

Definition

Let nN with n1, let either pQ with p1 or p=, and let AGLn(R) be an invertible real matrix (Invertible matrices and the general linear group GLn(F)), so that the linear system Ax=b has the unique solution x=A1b for every right-hand side bRn. The condition number of the linear system (equivalently, of the matrix A) with respect to the induced p-norm of The matrix norm induced by a published vector p-norm, using its separately defined infinity case when p=, is

κp(A)  :=  ApA1p    [1,+).

The value is at least one and is never infinite. The inverse A1 is the unique two-sided inverse of A (Invertible matrices and the general linear group GLn(F)), so AA1=In and A1A=In. For rational finite p, submultiplicativity and normalisation are Induced matrix norms are compatible with matrix-vector multiplication, submultiplicative, and satisfy ||I|| = 1. For p=, the same properties follow directly from the defining supremum: AxAx and applying this estimate twice gives submultiplicativity, while Inx=x gives In=1. Hence in either case

1=Inp=AA1pApA1p=κp(A).

Equivalently, κp(A) is the product of the largest factor by which A stretches a nonzero vector and the largest factor by which A1 stretches one. Applying the same estimate to A1 in place of A gives κp(A1)=κp(A).

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