Alphabeta Math
DefinitionDefinition: Literature-sourcedProof: Not applicablePipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Discounted returns and policy values in a finite MDP

Definition

Let a finite MDP have 0≤γ<1 and let π be a stationary Markov policy. If S=∅, define Vπ to be the unique empty function; no path law or choice axiom is needed in this case. If S≠∅, assume the Axiom of Choice and, for each s∈S, use the path law started at X0=(s,0) supplied by the policy-induced reward-state chain; write Xt=(St,Rt). The discounted return is

Gt=∑j=0∞γjRt+j+1,

and the state value under π is Vπ(s)=Eπ,s[G0], where Eπ,s is expectation under that start-state law. If S=∅, Vπ is the unique empty function. The reward sequence bound gives ∣Gt∣≤M/(1−γ), so each return is measurable and integrable. This is the start-state meaning of Eπ[Gt∣St=s] when that conditional expectation is defined. The definition concerns discounted infinite-horizon tasks; average-reward and undiscounted continuing models, and improper episodic tasks, are outside its scope.

The coordinate 0 in X0=(s,0) is only a dummy initial reward; the chain's one-step kernel emits rewards in R. Finite partial sums of the return are measurable, their pointwise limit is measurable, and the constant bound M/(1−γ) is an integrable majorant on the probability space.

Definition references

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