Alphabeta Math
DefinitionDefinition: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The multiplicative Bernstein presentation of the affine Hecke algebra of type A

Definition

Let n≥2, R0=Z[Q,Q−1], and A=R0[X1±1,…,Xn±1] as in The type-A weight lattice, Laurent ring, and divided differences. Let F be the free associative unital R0-algebra on symbols T1,…,Tn−1,X1±1,…,Xn±1 and let I be the two-sided ideal generated by the following relations:

  1. The Xj commute and XjXj−1=Xj−1Xj=1.
  2. (Ti−Q)(Ti+1)=0 for 1≤i<n.
  3. The Ti satisfy the type-An−1 braid relations: TiTi+1Ti=Ti+1TiTi+1 for 1≤i<n−1, and TiTj=TjTi when ∣i−j∣>1.
  4. The Bernstein cross-relations on the Laurent generators are
TiXj=si(Xj)Ti+(Q−1)Di(Xj)(1≤i<n, 1≤j≤n).

Define

Hnaff:=F/I.

The coefficient map A→Hnaff sends each Laurent monomial to the corresponding word in the Xj; its injectivity and the resulting A-module basis are the conclusion of Bernstein PBW basis for the affine Hecke algebra of type A ↗, not an assumption in this definition. The normalization is multiplicative: Q is a unit, Ti2=(Q−1)Ti+Q, and Ti is invertible. It matches the finite Hecke normalization of The reversal anti-involution, generator invertibility, the bar operator and the multiplicative normalization under Q=v2 and Ti=vUi, where (Ui−v)(Ui+v−1)=0.

Facts & Assumptions

Given: n≥2, the Laurent algebra A, its type-A action and divided differences, and the free associative algebra and quotient convention.

[F1]

The type-A weight lattice, Laurent ring, and divided differences: A is generated as a commutative R0-algebra by Xj±1, Di(f)∈A, and Di(fg)=Di(f)g+si(f)Di(g).

[F2]

The free associative R-algebra on a set and descent of relations: the free associative algebra on a generator set exists over any commutative coefficient ring, and quotienting by the two-sided ideal of the listed relations defines the presented unital associative algebra with its universal property.

[F3]

The reversal anti-involution, generator invertibility, the bar operator and the multiplicative normalization: in the finite Coxeter Hecke algebra, if the odd-connected type-A generators share parameter v, then Ui satisfies (Ui−v)(Ui+v−1)=0, and Ti=vUi, Q=v2 gives (Ti−Q)(Ti+1)=0.

Proof

Given: The data of the Definition.

1.1givenF2

The coefficient ring R0=Z[Q,Q−1] is commutative and Q is a unit. By [F2], the free associative algebra F and the two-sided ideal generated by the displayed relation set exist, so Hnaff=F/I is a unital associative R0-algebra with the stated generator-and-relation interpretation.

1.2F1algebra

The divided differences on the Laurent generators are Di(Xi)=−Xi+1, Di(Xi+1)=Xi+1, and Di(Xj)=0 when j∉{i,i+1}, directly from their definition and the action of si. Substitution into relation 4 gives TiXi−Xi+1Ti=−(Q−1)Xi+1, TiXi+1−XiTi=(Q−1)Xi+1, and TiXj=XjTi for the other variables.

2.1F1step 1.2algebra

If the Bernstein relation holds for f,g∈A, then using it twice and [F1] gives Ti(fg)−si(fg)Ti=(Q−1)(Di(f)g+si(f)Di(g))=(Q−1)Di(fg). For invertible f∈A, the Leibniz rule applied to ff−1=1 gives Di(f−1)=−si(f)−1Di(f)f−1. From Tif=si(f)Ti+(Q−1)Di(f), multiply on the right by f−1 and on the left by si(f)−1 to obtain Tif−1−si(f)−1Ti=−(Q−1)si(f)−1Di(f)f−1=(Q−1)Di(f−1). Since every Laurent monomial is a product of the Xj and their inverses, additivity and induction on products prove the Bernstein relation for every f∈A.

2.2step 1.2algebra

The quadratic relation is equivalent to Ti2=(Q−1)Ti+Q, so step 1.2 gives TiXiTi=Xi+1Ti2−(Q−1)Xi+1Ti=QXi+1. Conversely, in an algebra satisfying Ti2=(Q−1)Ti+Q, with Q∈R0×, and TiXiTi=QXi+1, multiplying the last equality on the right by Ti and using the quadratic relation gives TiXi−Xi+1Ti=−(Q−1)Xi+1; multiplying on the left by Ti gives TiXi+1−XiTi=(Q−1)Xi+1. Together with the stated commutation for j∉{i,i+1}, these are exactly the generator cross-relations of part 4. Thus the Bernstein relations and the compact relation are equivalent under the declared conventions.

3.1F3algebra∎

The quadratic relation gives Ti(Ti−(Q−1))=Q=(Ti−(Q−1))Ti. Since Q is a unit, Ti−1=Q−1(Ti−(Q−1)), proving the invertibility claim. The finite Hecke normalization agrees with [F3]: substituting Ti=vUi and Q=v2 into (Ui−v)(Ui+v−1)=0 gives (Ti−Q)(Ti+1)=v2(Ui−v)(Ui+v−1)=0. Every finite braid word has the same number of generators on each side, so scaling every generator by v multiplies both sides by the same power of v and preserves the braid relations.

Remarks

The quotient presentation itself does not assume a PBW basis or faithful inclusion of A. The theorem listed in justified_by proves that inclusion and the A-module basis.

Depends on

Used by

Dependency tree · two levels

33 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources