How statement and proof provenance work
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Null-cobordant closed manifolds
Definition
A closed smooth -manifold is null-cobordant if it is cobordant to the empty -manifold, that is, if there is a bordism from to (Unoriented smooth cobordism of closed manifolds).
Unwinding the bordism data, this is equivalent to the following statement: there is a compact smooth -manifold whose boundary is carried by a collar onto all of , so that and restricts to a diffeomorphism (Smooth collars of a manifold boundary, Diffeomorphisms and local diffeomorphisms of manifolds). Indeed, for a bordism to the empty manifold the outgoing boundary part is empty, hence ; conversely such a collar gives a bordism from to by taking , and the empty map. Thus, informally, is null-cobordant exactly when is (diffeomorphic to) the whole boundary of a compact smooth -manifold.
In the oriented theory, a closed oriented -manifold is null-cobordant if it is oriented cobordant to the empty oriented manifold (Oriented smooth cobordism). Because the incoming face contributes the negative orientation, a null-cobordism satisfies: the induced boundary orientation of the whole boundary is . Thus is null-cobordant exactly when occurs as the orientation opposite to the induced boundary orientation of some compact oriented -manifold; reversing the orientation of presents as the induced boundary with its outward-normal-first orientation. The empty manifold carries its unique orientation and is null-cobordant in both theories, being cobordant to itself by the cylinder.
Null-cobordism depends only on the cobordism class: if is cobordant to and is null-cobordant, then is cobordant to and to , and transitivity of the cobordism relation (Smooth cobordism is an equivalence relation) gives that is null-cobordant; the same holds in the oriented theory. The definition uses no choice principle.
Depends on
Used by
- The real projective plane is not unoriented null-cobordant Counterexample
- Unoriented and oriented bordism groups Definition
- A circle is the boundary of a disk Example
- Signed points give the oriented zero-bordism invariant Example
- Two unoriented points bound an interval Example
- Boundaries have zero Stiefel-Whitney numbers Proposition
- Oriented boundaries have zero Pontryagin numbers Proposition
- Zero-dimensional bordism groups Proposition
- Cartesian product makes bordism a graded ring Theorem
- Disjoint union makes bordism classes abelian groups Theorem
Dependency tree · two levels
29 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Daniel S. Freed, Bordism: Old and New (lecture notes, UT Austin, Fall 2012) (standard reference, not scraped)
- Andrew Ranicki, Algebraic and Geometric Surgery (Oxford Mathematical Monographs, 2002) (standard reference, not scraped)