Alphabeta Math
DefinitionDefinition: AI-adaptedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Admissible polynomial pair for Hermitian-reflection QSP

Definition

For an integer d≥0, a pair P,Q∈C[x] is QSP-admissible of degree bound d when:

  • P=0 or deg⁡P≤d, and every exponent with nonzero coefficient in P is congruent to d modulo 2;
  • Q=0 or deg⁡Q≤d−1, and every exponent with nonzero coefficient in Q is congruent to d−1 modulo 2;
  • the formal polynomial identity PP∗+(1−x2)QQ∗=1 holds, where P∗(x)=∑kpk‾xk if P(x)=∑kpkxk.

The zero polynomial satisfies every degree bound and both parity conditions. On real x, coefficient conjugation gives P∗(x)=P(x)‾. The bound d is nominal; a polynomial may have smaller degree of the same parity.

Facts & Assumptions

Given: An integer d≥0 and an admissible pair P,Q as defined above.

[F1]

Real and imaginary parts, complex conjugation, and modulus: complex conjugation fixes real numbers and ∣z∣2=zz‾≥0.

Verification

1.1givenF1algebra

For real x, conjugating each coefficient of P and using x=x‾ gives P∗(x)=P(x)‾; the same calculation gives Q∗(x)=Q(x)‾. Hence the polynomial identity implies ∣P(x)∣2+(1−x2)∣Q(x)∣2=1 for every real x.

2.1step 1.1algebra∎

If ∣x∣≤1, then both summands are nonnegative, so ∣P(x)∣2≤1 and (1−x2)∣Q(x)∣2≤1. Taking nonnegative square roots yields ∣P(x)∣≤1 and 1−x2∣Q(x)∣≤1. At d=0 the degree convention forces Q=0, so the second bound also holds at both endpoints.

Depends on

Used by

Dependency tree · two levels

20 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources