Alphabeta Math
DefinitionDefinition: Literature-sourcedProof: AI-adaptedPipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Logical block error and leakage amplitude

Definition

Let J:C→V be a fixed-charge encoding, P=JJ∗ its code projector, U∈U(C) a logical target, and W∈U(V) an ambient unitary. Its zero-on-the-complement target extension is U~:=JUJ∗:V→V. Define the logical block error and leakage amplitude by ϵlog(W,U):=∥PWP−U~∥op,ϵleak(W):=∥(I−P)WP∥op. Both are finite operator norms. The first measures the compressed block against the target; the second measures transfer from the code into its orthogonal complement. They diagnose different errors.

Facts & Assumptions

Given: A finite-dimensional encoding J:C→V, its projector P, a logical unitary U, and an ambient unitary W.

[F1]

P is the orthogonal projection onto JC. Fixed-charge encoding and code projector

[F2]

The operator norm is finite for every linear map between finite-dimensional inner-product spaces. The operator norm is zero on the zero domain and otherwise is max_{||v||=1} ||Tv||

Proof

1.1givenF1F2

The maps PWP−U~ and (I−P)WP are endomorphisms of V. Because V is finite dimensional, [F2] assigns a finite operator norm to each map; the two quantities are therefore well defined.

2.1givenF1F2algebra∎

For a zero-leakage but logically incorrect boundary case, take V=C=C2, J=P=I, W=I, and U=diag⁡(1,−1). Then ϵleak=0 and ϵlog=∥I−U∥op=2. This proves the two quantities are not interchangeable.

Depends on

Used by

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources