Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-08-30
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A chain map computed on cycles, boundaries, and homology

Example

Let C∙ be the two-term complex 0→Z→×2Z→0, and let D∙ be 0→Z→×4Z→0. The maps f1=1Z and f0=×2 define a chain map f:C→D. It induces the zero map on H1 and the inclusion Z/2Z→Z/4Z,xˉ↦2x‾, on H0.

Facts & Assumptions

Given: The complexes C∙,D∙ and the family f1=1Z, f0=×2.

[L1]

Ab is an abelian category (Abelian groups form an abelian category).

[L2]

A chain map induces a well-defined homology map (A chain map induces a well-defined map on homology).

Verification

technique · direct
1.1L1givenalgebra

The chain condition holds because (×4)∘1Z=(×2)∘(×2). Also Z1(C)=Z1(D)=0, B0(C)=2Z, and B0(D)=4Z. Hence H1(C)=H1(D)=0, H0(C)≅Z/2Z, and H0(D)≅Z/4Z.

2.1L2step 1.1∎

By [L2], the induced homology map comes from the degree-0 map f0=×2 on cycles. It sends the boundary subgroup 2Z into 4Z, so on quotients it is xˉ⟼2x‾. In degree 1 the homology groups are zero, so the induced map there is zero.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources