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ExampleConstruction: Literature-sourcedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (z-ai/glm-5.2)verified 2026-07-29 (claude-fable-5)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A finite Hausdorff space is discrete, and its diagonal is closed for the trivial reason that every subset of the square is

Example

Let (X,T)(X, \mathcal{T}) be a Hausdorff space (Hausdorff space: distinct points have disjoint open neighbourhoods; every metrizable space is Hausdorff and the indiscrete topology on two points is not) whose underlying set is finite (Finite, countably infinite, countable, uncountable). Then:

  1. T\mathcal{T} is the discrete topology on XX (The discrete, indiscrete, cofinite, cocountable, particular-point and Sierpinski topologies): every subset of XX is open.
  2. X×XX \times X with the product topology (The product set iIXi\prod_{i \in I} X_i of functions choosing a point in each factor, the projections, the box topology, and the product topology as the initial topology of the projections; the empty product is a one-point space) is discrete as well, so every subset of it — the diagonal ΔX\Delta_X included — is both open and closed.

Clause 2 makes the diagonal criterion (A space is Hausdorff if and only if its diagonal is closed in the square carrying the product topology) true here for a reason that has nothing to do with the diagonal: in a discrete square every subset is closed. The example is worth recording precisely because it is the degenerate case, where the criterion carries no information.

Facts & Assumptions

Given: A Hausdorff space (X,T)(X,\mathcal{T}) with XX finite, and X×XX \times X with the product topology.

Verification

technique · direct
1.1

XX is T1T_1, being Hausdorff.

L1
2.1

Every subset AXA \subseteq X is finite by [A1], hence closed by step 1.1 and [L2]; so every subset of XX is closed.

step 1.1A1L2
3.1

Every subset AXA \subseteq X is open, its complement XAX \setminus A being a subset of XX and therefore closed by step 2.1; so T\mathcal{T} is the discrete topology, which is claim 1.

step 2.1A2
4.1

Every singleton {(u,v)}={u}×{v}\{(u,v)\} = \{u\} \times \{v\} of X×XX \times X is a basic open box by step 3.1 and [A3], so every subset of X×XX \times X, being the union of the singletons of its elements, is open; hence X×XX \times X is discrete and every subset of it, ΔX\Delta_X included, is closed. This is claim 2.

step 3.1A2A3

Remarks

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 87 results over 24 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources