How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
A large almost-pure pair extends an anticomplete blockade
Example
Let
and assume:
- is anticomplete to ;
- is anticomplete to ;
- inside there are disjoint subsets with anticomplete to .
Then is an anticomplete blockade, and replacing the last block by the pair produces the longer anticomplete blockade .
Facts & Assumptions
Given: The blocks and the subsets with the adjacency relations stated in the example.
A blockade is an ordered sequence of pairwise disjoint nonempty vertex sets (Blockades, their length, their width, and their support).
A pair of disjoint vertex sets is anticomplete exactly when there are no edges between them (Edges between disjoint vertex sets; complete, anticomplete, pure and mixed pairs).
Verification
The sets are pairwise disjoint and nonempty, so is a blockade by [L1]. Hypotheses 1 and 2 say that each earlier block is anticomplete to every later block, so [L2] makes it an anticomplete blockade.
The sets and are disjoint nonempty subsets of , and hypothesis 3 says that is anticomplete to . Hypothesis 2 also implies that both and are anticomplete to . Therefore every earlier block in is anticomplete to every later block.
By steps 1.1 and 1.2, replacing the last block by the anticomplete pair extends the original anticomplete blockade by one step.
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Shenwei Huang, Yiao Ju, and Yidong Zhou, Erdos-Hajnal beyond the five-vertex path, proof of Lemma 2.8 (standard reference, not scraped)