Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedprecheck passaudited 2026-09-04
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A large almost-pure pair extends an anticomplete blockade

Example

Let

B0={u1,u2},B1={v1,v2},B2={w1,w2,w3,w4,w5,w6},

and assume:

  1. B0 is anticomplete to B1;
  2. B0B1 is anticomplete to B2;
  3. inside B2 there are disjoint subsets X={w1,w2},Y={w3,w4,w5,w6}, with Y anticomplete to X.

Then (B0,B1,B2) is an anticomplete blockade, and replacing the last block B2 by the pair (X,Y) produces the longer anticomplete blockade (B0,B1,X,Y).

Facts & Assumptions

Given: The blocks B0,B1,B2 and the subsets X,YB2 with the adjacency relations stated in the example.

[L1]

A blockade is an ordered sequence of pairwise disjoint nonempty vertex sets (Blockades, their length, their width, and their support).

[L2]

A pair of disjoint vertex sets is anticomplete exactly when there are no edges between them (Edges between disjoint vertex sets; complete, anticomplete, pure and mixed pairs).

Verification

technique · direct
1.1

The sets B0,B1,B2 are pairwise disjoint and nonempty, so (B0,B1,B2) is a blockade by [L1]. Hypotheses 1 and 2 say that each earlier block is anticomplete to every later block, so [L2] makes it an anticomplete blockade.

L1L2given
1.2

The sets X and Y are disjoint nonempty subsets of B2, and hypothesis 3 says that Y is anticomplete to X. Hypothesis 2 also implies that both X and Y are anticomplete to B0B1. Therefore every earlier block in (B0,B1,X,Y) is anticomplete to every later block.

givenL2
2.1

By steps 1.1 and 1.2, replacing the last block B2 by the anticomplete pair (X,Y) extends the original anticomplete blockade by one step.

step 1.1step 1.2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources