Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedprecheck passverified 2026-08-06 (claude-opus-5)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A four-pair relation on {∅,{∅},{∅,{∅}}} with its domain, range, field, inverse, restriction, image and self-composite computed

Example

Write u:=∅, v:={∅} and w:={∅,{∅}}; these are pairwise distinct, since u has no element, v has exactly the element u, and w has v as an element while v does not. Put A:={u,v}∪{w} and

R:={(u,v),(v,w)}∪{(w,u),(u,u)}.

Then R is a relation on A with

dom⁡R=ran⁡R=fld⁡R=A,R−1={(v,u),(w,v)}∪{(u,w),(u,u)},

R↾{u}={(u,v),(u,u)},R[{u}∪{v}]=A,R∘R={(u,w),(u,v)}∪{(u,u),(v,u)}∪{(w,v),(w,u)}.

Facts & Assumptions

Given: u:=∅, v:={∅}, w:={∅,{∅}}, A:={u,v}∪{w} and R as displayed.

[L2]

dom⁡R:={ a:∃b (a,b)∈R },ran⁡R:={ b:∃a (a,b)∈R } (Relation, dom⁡R, ran⁡R, fld⁡R, and the specialisations "relation from A to B" and "relation on A").

[L3]

(b,a)∈R−1 holds if and only if (a,b)∈R; (a,c)∈S∘R holds if and only if (a,b)∈R and (b,c)∈S for some b; and (a,b)∈R↾A holds if and only if (a,b)∈R and a∈A (The inverse relation R−1, the composite S∘R, and the restriction R↾A).

[L4]

b∈R[A] holds if and only if (a,b)∈R for some a∈A (The image R[A] and the preimage R−1[B] of a set under a relation).

[L5]

(a,b)=(c,d) if and only if a=c and b=d ((a,b)=(c,d) if and only if a=c and b=d).

[L6]
[L7]

{x,y} is the set whose elements are exactly x and y, and {x}:={x,x} (The unordered pair {x,y} and the singleton {x}={x,x}).

[L8]

There is exactly one set with no elements, written ∅ (There is exactly one set with no elements, written ∅).

[L10]

z∈A×B holds if and only if z=(a,b) for some a∈A and some b∈B (The Cartesian product A×B:={ z∈P(P(A∪B)):∃a∈A ∃b∈B z=(a,b) }).

[L11]

If every z satisfies z∈x if and only if z∈y, then x=y (The Axiom of Extensionality: ∀x ∀y (∀z (z∈x↔z∈y)→x=y)).

Verification

technique · direct
1.1

u, v and w are pairwise distinct and A has exactly them as elements; every element of R is an ordered pair with both coordinates in A, so R is a relation on A, that is R⊆A×A.

L1L6L7L8L9L10L12
2.1

Reading off first coordinates gives u, v, w, so dom⁡R=A; reading off second coordinates gives v, w, u, so ran⁡R=A; and the field, being the union of the two, is A as well.

L2L5L9L11step 1.1
2.2

Reversing each pair gives R−1={(v,u),(w,v)}∪{(u,w),(u,u)}; keeping the pairs whose first coordinate is u gives R↾{u}={(u,v),(u,u)}; and the elements related to u or to v are v, u and w, so R[{u}∪{v}]=A.

L3L4L5L7L9L11step 1.1
2.3

For the self-composite, each pair (a,b) of R is matched with every pair of R whose first coordinate is b: from (u,v) and (v,w) comes (u,w); from (u,u) and the two pairs starting at u come (u,v) and (u,u); from (v,w) and (w,u) comes (v,u); and from (w,u) and the two pairs starting at u come (w,v) and (w,u). These six pairs are exactly the displayed R∘R.

L3L5L9L11step 1.1
3.1

The domain, range, field, inverse, restriction, image and self-composite are as displayed.

step 2.1step 2.2step 2.3∎

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

22 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources