Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passverified 2026-08-06 (claude-opus-5)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A four-pair relation on {,{},{,{}}}\{\varnothing,\{\varnothing\},\{\varnothing,\{\varnothing\}\}\} with its domain, range, field, inverse, restriction, image and self-composite computed

Example

Write u:=u := \varnothing, v:={}v := \{\varnothing\} and w:={,{}}w := \{\varnothing,\{\varnothing\}\}; these are pairwise distinct, since uu has no element, vv has exactly the element uu, and ww has vv as an element while vv does not. Put A:={u,v}{w}A := \{u,v\} \cup \{w\} and

R:={(u,v),(v,w)}{(w,u),(u,u)}.R := \{(u,v),(v,w)\} \cup \{(w,u),(u,u)\}.

Then RR is a relation on AA with

domR=ranR=fldR=A,R1={(v,u),(w,v)}{(u,w),(u,u)},\operatorname{dom} R = \operatorname{ran} R = \operatorname{fld} R = A, \qquad R^{-1} = \{(v,u),(w,v)\} \cup \{(u,w),(u,u)\},

R{u}={(u,v),(u,u)},R[{u}{v}]=A,RR={(u,w),(u,v)}{(u,u),(v,u)}{(w,v),(w,u)}.R \restriction \{u\} = \{(u,v),(u,u)\}, \qquad R[\{u\} \cup \{v\}] = A, \qquad R \circ R = \{(u,w),(u,v)\} \cup \{(u,u),(v,u)\} \cup \{(w,v),(w,u)\}.

Facts & Assumptions

Given: u:=u := \varnothing, v:={}v := \{\varnothing\}, w:={,{}}w := \{\varnothing,\{\varnothing\}\}, A:={u,v}{w}A := \{u,v\} \cup \{w\} and RR as displayed.

[L2]

domR:={a:b (a,b)R},ranR:={b:a (a,b)R}\operatorname{dom} R := \{\, a : \exists b\ (a,b) \in R \,\}, \qquad \operatorname{ran} R := \{\, b : \exists a\ (a,b) \in R \,\} (Relation, domR\operatorname{dom} R, ranR\operatorname{ran} R, fldR\operatorname{fld} R, and the specialisations "relation from AA to BB" and "relation on AA").

[L3]

(b,a)R1(b,a) \in R^{-1} holds if and only if (a,b)R(a,b) \in R; (a,c)SR(a,c) \in S \circ R holds if and only if (a,b)R(a,b) \in R and (b,c)S(b,c) \in S for some bb; and (a,b)RA(a,b) \in R \restriction A holds if and only if (a,b)R(a,b) \in R and aAa \in A (The inverse relation R1R^{-1}, the composite SRS \circ R, and the restriction RAR \restriction A).

[L4]

bR[A]b \in R[A] holds if and only if (a,b)R(a,b) \in R for some aAa \in A (The image R[A]R[A] and the preimage R1[B]R^{-1}[B] of a set under a relation).

[L5]

(a,b)=(c,d)(a,b) = (c,d) if and only if a=ca = c and b=db = d ((a,b)=(c,d)(a,b) = (c,d) if and only if a=ca = c and b=db = d).

[L6]

(a,b):={{a},{a,b}}(a,b) := \{\{a\},\{a,b\}\} (The Kuratowski ordered pair (a,b):={{a},{a,b}}(a,b) := \{\{a\},\{a,b\}\}).

[L7]

{x,y}\{x,y\} is the set whose elements are exactly xx and yy, and {x}:={x,x}\{x\} := \{x,x\} (The unordered pair {x,y}\{x,y\} and the singleton {x}={x,x}\{x\} = \{x,x\}).

[L8]

There is exactly one set with no elements, written \varnothing (There is exactly one set with no elements, written \varnothing).

Verification

technique · direct
1.1

uu, vv and ww are pairwise distinct and AA has exactly them as elements; every element of RR is an ordered pair with both coordinates in AA, so RR is a relation on AA, that is RA×AR \subseteq A \times A.

L1L6L7L8L9L10L12
2.1

Reading off first coordinates gives uu, vv, ww, so domR=A\operatorname{dom} R = A; reading off second coordinates gives vv, ww, uu, so ranR=A\operatorname{ran} R = A; and the field, being the union of the two, is AA as well.

L2L5L9L11step 1.1
2.2

Reversing each pair gives R1={(v,u),(w,v)}{(u,w),(u,u)}R^{-1} = \{(v,u),(w,v)\} \cup \{(u,w),(u,u)\}; keeping the pairs whose first coordinate is uu gives R{u}={(u,v),(u,u)}R \restriction \{u\} = \{(u,v),(u,u)\}; and the elements related to uu or to vv are vv, uu and ww, so R[{u}{v}]=AR[\{u\} \cup \{v\}] = A.

L3L4L5L7L9L11step 1.1
2.3

For the self-composite, each pair (a,b)(a,b) of RR is matched with every pair of RR whose first coordinate is bb: from (u,v)(u,v) and (v,w)(v,w) comes (u,w)(u,w); from (u,u)(u,u) and the two pairs starting at uu come (u,v)(u,v) and (u,u)(u,u); from (v,w)(v,w) and (w,u)(w,u) comes (v,u)(v,u); and from (w,u)(w,u) and the two pairs starting at uu come (w,v)(w,v) and (w,u)(w,u). These six pairs are exactly the displayed RRR \circ R.

L3L5L9L11step 1.1
3.1

The domain, range, field, inverse, restriction, image and self-composite are as displayed.

step 2.1step 2.2step 2.3

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 25 results over 13 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources