Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-08-30 rests on unproved material (inherited)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Rests on 3 statements not proved in this library, by way of the results it cites. This item cites no such statement directly; it depends on results that do. The unproved premises it inherits are Cohen's first model: an infinite Dedekind-finite set of reals, Sierpiński 1947: the generalised continuum hypothesis implies the Axiom of Choice and The continuum hypothesis and its generalisation are independent of ZFC. Each is recorded with a citation to the literature and is not established here, because the track that would prove it has not yet been developed in this library. Everything else in this proof is proved here.

A subcomplex and its quotient complex

Example

Let C be the two-term complex 0Z×2Z0, and let S be the subcomplex with S1=0 and S0=2Z. Then the quotient complex C/S is 0Z0Z/2Z0.

Facts & Assumptions

Given: The complexes C and S just displayed.

[L1]

A subcomplex is a degreewise subobject stable under the differentials (Subcomplex).

[L2]

A quotient complex is obtained by quotienting degreewise and descending the differential (Quotient complex).

[L3]

Ab is an abelian category (Modules over a ring form an abelian category).

Verification

technique · direct
1.1

The family S is a subcomplex: the only nontrivial check is that d1(S1)=0 lands in 2Z=S0. Thus [L1] applies.

L1L3givenalgebra
2.1

By [L2], the quotient has terms C1/S1Z and C0/S0Z/2Z. The descended differential is zero because 2x lies in 2Z for every representative xZ, so changing representatives does not change the class. Hence the quotient complex is as displayed.

L2step 1.1algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources