Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Finite ABC-SMC particles can miss target support despite a valid mixture weight

Example

Let Θ={0,1} have the uniform prior and Y={0,1,2}. The simulator has K(0,{0})=K(0,{1})=12 and K(0,{2})=0, while K(1,{0})=14, K(1,{1})=12, and K(1,{2})=14. Take S(0)=S(1)=0, S(2)=1, s0=0, and ϵ1=12. Let the previous two-particle population be (0,0) with equal weights and use the stage-1 kernel Q1(0,{0})=99100, Q1(0,{1})=1100, with the same row from θ=1. The proposal mixture has full prior support, and its Radon–Nikodym weights are finite.

Verification

Given: The stage-1 prior, simulator, tolerance event, proposal mixture, and particle count N=2 specified in the Example.

[F1] Sequential ABC importance-resampling with tolerance populations: a candidate receives weight 1Aϵ1(Y)dΠ/dϕ1N(θ), and a zero-total-weight population is reported as degenerate.

[F2] Sequential ABC Radon–Nikodym weights target each tolerance law: the theorem does not claim that a finite self-normalized particle population represents all positive target mass.

1.1F1givenalgebra

The proposal masses are ϕ1N({0})=99/100 and ϕ1N({1})=1/100, so the uniform prior is dominated and the finite RN weights are r1N(0)=50/99 and r1N(1)=50. Tolerance acceptance is certain at θ=0 and has probability 3/4 at θ=1, so Zϵ1=1/2+(1/2)(3/4)=7/8 and the unnormalized target mass at θ=1 is 3/8, giving normalized mass 3/7.

2.1F1step 1.1algebra

Each proposal has parameter 0 with probability 99/100, independently conditional on the previous population, so both have parameter 0 with probability (99/100)2=9801/10000; on this event both weights equal 50/99 and the normalized empirical measure assigns zero mass to θ=1.

3.1F1F2step 1.1step 2.1algebra∎

Step 1.1 gives true target mass 3/7 at θ=1, whereas the positive-probability event in step 2.1 has no empirical mass there; any resampled offspring also stay at θ=0. This illustrates the finite-particle caveat in [F2] despite valid support and weights.

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