How statement and proof provenance work
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Finite ABC-SMC particles can miss target support despite a valid mixture weight
Example
Let have the uniform prior and . The simulator has and , while , , and . Take , , , and . Let the previous two-particle population be with equal weights and use the stage-1 kernel , , with the same row from . The proposal mixture has full prior support, and its Radon–Nikodym weights are finite.
Verification
Given: The stage-1 prior, simulator, tolerance event, proposal mixture, and particle count specified in the Example.
[F1] Sequential ABC importance-resampling with tolerance populations: a candidate receives weight , and a zero-total-weight population is reported as degenerate.
[F2] Sequential ABC Radon–Nikodym weights target each tolerance law: the theorem does not claim that a finite self-normalized particle population represents all positive target mass.
The proposal masses are and , so the uniform prior is dominated and the finite RN weights are and . Tolerance acceptance is certain at and has probability at , so and the unnormalized target mass at is , giving normalized mass .
Each proposal has parameter with probability , independently conditional on the previous population, so both have parameter with probability ; on this event both weights equal and the normalized empirical measure assigns zero mass to .
Step 1.1 gives true target mass at , whereas the positive-probability event in step 2.1 has no empirical mass there; any resampled offspring also stay at . This illustrates the finite-particle caveat in [F2] despite valid support and weights.
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Sources
- Osvaldo A. Martin, Ravin Kumar, and Junpeng Lao, Bayesian Modeling and Computation in Python, Chapter 8 (standard reference, not scraped)
- Jarno Lintusaari, Michael U. Gutmann, Ritabrata Dutta, Samuel Kaski, and Jukka Corander, Fundamentals and Recent Developments in Approximate Bayesian Computation, §5.2 (standard reference, not scraped)