Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Abel convergence of the alternating harmonic power series along a nonradial Stolz approach

Example

For k2, put zk=11/k+i/(2k). Then zk<1, zk1 nonradially within one Stolz region, and n=1(1)n+1zknnlog2.

Facts & Assumptions

Given: The sequence (zk) and the alternating harmonic coefficients.

[L1]

The alternating harmonic series converges to log2 ([The power series for log(1+x) on (-1,1], including the Abel endpoint](/item/thm-log-one-plus-x-power-series)).

[L2]

Abel's theorem recovers a convergent series along every fixed Stolz approach to 1 (Abel's limit theorem: a convergent complex series is recovered by its power series along every Stolz approach to 1).

Verification

technique · direct
1.1

Direct calculation gives zk2=12/k+5/(4k2)<1 for k2, and 1zk=5/(2k).

algebra
2.1

Since 1zk=(1zk2)/(1+zk), step 1.1 gives a uniform bound on 1zk/(1zk), so (zk) lies in one Stolz region and tends to 1.

step 1.1algebra
3.1

Apply [L2] to the series in [L1]. The nonzero imaginary part makes the approach nonradial.

step 2.1L1L2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

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