Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-02
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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The power series for log(1+x) on (-1,1], including the Abel endpoint

Statement

For −1<x≤1, log⁡(1+x)=∑n=1∞(−1)n+1xnn. The series converges at x=1 to log⁡2 and diverges at x=−1.

Facts & Assumptions

Given: A real x with −1<x<1.

[L1]

log⁡′(u)=1/u on (0,∞), so (log⁡(1+x))′=1/(1+x) and log⁡1=0 (The natural logarithm has derivative 1/x and equals the integral from 1 to x of 1/t).

[L2]
[L3]

A real power series may be integrated term by term inside its radius of convergence (Inside its radius a real power series may be integrated term by term on every closed subinterval).

Proof

technique · direct
1.1

Integrating the series of [L2] from 0 to x gives ∑n≥1(−1)n+1xn/n.

L2L3
2.1

By [L1], the integral of 1/(1+t) from 0 to x is log⁡(1+x), so the displayed series formula holds for −1<x<1.

L1step 1.1
3.1

At x=1 the series is alternating harmonic and converges by [L4]; Abel's theorem and step 2.1 identify its sum with log⁡2.

step 2.1L4
4.1

At x=−1 every term is −1/n, so the series is the negative harmonic series and diverges.

L4algebra∎

Depends on

Used by

Dependency tree · two levels

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Sources