Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck pass
How statement and proof provenance work

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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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These labels describe origin, not correctness: citations and verification chips remain separate evidence.

An expanding cell preserves a constant state

Statement

On a two-cell periodic grid take Δξ=1, Δt=0.1, period L=2, initial faces x1/2=0, x3/2=1, x5/2=2, physical speed a=0, and periodic face velocities w1/2=0, w3/2=0.1, w5/2=0. If both initial cell averages equal U∈R, the successful ALE upwind step has Jacobians 1.01 and 0.99, preserves both averages at U, and conserves total mass 2U.

Facts & Assumptions

Given: The grid, time step, face velocities, physical speed, and constant initial average in the Statement.

[F1]

Periodic one-dimensional moving grid: Jin=(xi+1/2n−xi−1/2n)/Δξ, the face update is xi+1/2n+1=xi+1/2n+Δt wi+1/2n, and ci+1/2=a−wi+1/2.

[F2]

Conservative upwind ALE finite-volume step: after checking Jin+1>0, the algorithm uses F^i+1/2=ci+1/2+uˉi+ci+1/2−uˉi+1 and Jin+1uˉin+1=Jinuˉin−(Δt/Δξ)(F^i+1/2−F^i−1/2).

[F3]

The upwind ALE step conserves mass and preserves constants: a successful periodic upwind ALE step preserves mass and every constant input state.

Verification

1.1givenF1F2algebra

The moved faces are 0, 1.01, and 2. Hence the two updated Jacobians are 1.01 and 0.99, both positive, so [F2] returns success and performs the state update.

1.2givenF1F2algebra

The relative speeds at these faces are 0, −0.1, and 0, so the fluxes are 0, −0.1U, and 0. Formula [F2] gives J1n+1uˉ1n+1=U−0.1(−0.1U)=1.01U and J2n+1uˉ2n+1=U−0.1(0.1U)=0.99U. Dividing by the positive Jacobians gives both updated averages equal to U.

2.1F1F3step 1.2algebra∎

The new total mass is 1.01U+0.99U=2U, equal to the old mass U+U. This is the finite instance of [F3].

Depends on

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