Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The arrow category Set\mathbf{Set}^{\to}: functions as objects and commuting squares as morphisms

Example

The functor category from the walking-arrow category to Set\mathbf{Set} is the arrow category Set\mathbf{Set}^{\to}.

Facts & Assumptions

Given: The walking-arrow category 2=(01)\mathbf 2=(0\to1).

[L1]

Objects and morphisms in a functor category are functors and natural transformations (Functor category [C,D][\mathcal C,\mathcal D]).

[L2]

Sets and functions form the category Set\mathbf{Set} (Sets and functions form the large locally small category Set\mathbf{Set}).

Verification

technique · direct
1.1

Let 2\mathbf 2 have objects 0,10,1, their identities, and one further arrow a:01a:0\to1. A functor F:2SetF:\mathbf2\to\mathbf{Set} is exactly a function F(a):F(0)F(1)F(a):F(0)\to F(1).

L1L2
2.1

Given functions f:XYf:X\to Y and g:XYg:X'\to Y', a natural transformation between their corresponding functors consists of maps u:XXu:X\to X' and v:YYv:Y\to Y' satisfying vf=guv f=g u. Thus it is exactly a commuting square.

step 1.1L1
3.1

Vertical composition composes the two side maps of commuting squares. It preserves the square equation, and identity transformations give identity squares. Therefore [2,Set][\mathbf2,\mathbf{Set}] is precisely Set\mathbf{Set}^{\to} as described.

step 2.1L1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 23 results over 11 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources