Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A real conic acquires complex points

Example

The real scheme X=Spec⁡R[x,y]/(x2+y2+1) has no R-valued points over R. Its complex base change is Spec⁡C[x,y]/(x2+y2+1) and has the complex point (i,0). Absence of real-valued points does not mean X is empty.

Facts & Assumptions

Given: The objects, hypotheses and conventions in the statement above.

[F1]

For every field K and scheme X, morphisms Spec⁡K→X correspond bijectively to pairs (x,ι) with x∈X and a field embedding ι:κ(x)→K. The identity embedding gives a canonical morphism Spec⁡κ(x)→X, compatible with all scheme morphisms. More generally, for a nonzero local ring (R,m), morphisms Spec⁡R→X correspond to pairs (x,φ) with a local homomorphism φ:OX,x→R. Assuming Choice, two field-valued points have the same image in X if and only if they are dominated by a common field-valued point, by compatible embeddings of their fields into a third field. (Field-valued points and local-ring points)

[F2]

For a field extension K/k and a k-scheme X, the inverse image of every affine open U=Spec⁡A in XK is Spec⁡(A⊗kK). These affine charts cover XK and are compatible on overlaps and with coefficient localizations. (Affine charts after extension of the ground field)

[F3]

Let A→C be a unital ring map. For any set of variables (ti) and any ideal I⊆A[ti], (A[ti]/I)⊗AC≅C[ti]/IC[ti]. Here the extended ideal is generated by the coefficient images of all elements of I. For a multiplicative subset M⊆A, (M−1A)⊗AC≅M‾−1C. These are ring isomorphisms; no flatness, finite-generation or nonzero-ring hypothesis is required. (Presentations and localization under base extension)

Verification

1.1givenF1algebra

A real-valued point over R gives a real algebra map to R, hence images a,b∈R satisfying a2+b2+1=0. This is impossible since the left side is at least 1. This agrees with the residue-field description of F1; the requirement that the morphism be over R is retained.

2.1F2F3algebra∎

F2 and F3 give the displayed complex ring. Evaluation x↦i,y↦0 kills its defining polynomial and sends 1 to 1, so it is a complex point. Its composition with the projection gives a point of X, proving X is nonempty. The same evaluation directly shows neither coordinate ring is zero.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources