Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedprecheck passaudited 2026-08-16
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Binary words avoiding 11 are counted by Fn+2

Example

Let an be the number of binary words of length n that avoid 11. Then

an=Fn+2,∑n≥0anxn=1+x1−x−x2.

The proper-prefix states ε,1 have transfer matrix

A=(1110).

Facts & Assumptions

Given: The singleton forbidden set B={11} over {0,1}.

[L1]

The Fibonacci numbers satisfy their recurrence and fixed initial values (The Fibonacci sequence F0=0,F1=1 and Lucas sequence L0=2,L1=1).

[L2]

The prefix automaton sends a state and letter to the longest allowed proper-prefix suffix, rejecting a completed forbidden factor (The longest-suffix prefix automaton for a finite set of forbidden factors).

[L3]

Fixed-entry walk generating functions are the corresponding cofactors of I−xA divided by its determinant (Transfer-matrix theorem: weighted-walk generating functions are cofactors of I−xA divided by det⁡(I−xA)).

Verification

technique · transfer matrix
1.1givenL2

By [L2], state ε has transitions labelled 0 to ε and 1 to 1, while state 1 has only the transition labelled 0 to ε. This gives the displayed matrix.

2.1step 1.1L3algebra

Every avoiding word labels one walk from ε to either state. Since I−xA=(1−x−x−x1), summing the first-row entries of its inverse via [L3] gives (1+x)/(1−x−x2).

3.1step 2.1L1algebra∎

Its coefficients begin a0=1,a1=2 and satisfy an+2=an+1+an, so comparison with [L1] gives an=Fn+2.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources