Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-08-30
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C4 shows that divisibility of irreducible degrees by ∣G∣ is not an equivalence

Example

The divisor 2 of ∣C4∣=4 is not the degree of any irreducible complex character of C4. So the theorem χ(1)∣∣G∣ is a necessary condition for irreducible degrees, not a characterization.

Facts & Assumptions

Given: The cyclic group C4.

[F2]

Every irreducible representation of a finite abelian group over a splitting field is one-dimensional (Every irreducible representation of a finite abelian group over a splitting field is one-dimensional).

[F3]

Irreducible complex character degrees divide the group order (The degree of an irreducible complex character divides ∣G∣).

Verification

technique · direct
1.1F1given

By [F1], C4 is a finite cyclic group of order 4, hence finite abelian.

2.1F2step 1.1algebra

Over C, every irreducible representation of the finite abelian group C4 has degree 1 by [F2]. Therefore no irreducible complex character of C4 has degree 2, even though 2∣4.

3.1F3step 2.1∎

This shows that [F3] is not an equivalence: a divisor of ∣G∣ need not occur as an irreducible degree.

Depends on

Used by

Dependency tree · two levels

21 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources